Các câu hỏi tương tự
Cho a,b,c là các số dương .CMR :
T = \(\frac{a}{3a+b+c}+\frac{b}{3b+a+c}+\frac{c}{3c+b+a}\le\frac{3}{5}\)
Cho các số dương a,b,c. CMR: \(T=\frac{a}{3a+b+c}+\frac{b}{3b+a+c}+\frac{c}{3c+a+b}\le\frac{3}{2}\)
\(a,b,c>0\).Chứng minh \(\frac{a}{3a+b+c}+\frac{b}{3b+c+a}+\frac{c}{3c+a+b}\le\frac{3}{5}\)
cho 3 số dương a,b,c.chung minh:\(\frac{b}{a+3b}+\frac{c}{b+3c}+\frac{a}{c+3a}\le\frac{3}{4}\)
CMR: Với mọi a;b;c>0
\(\frac{2b+3c}{a+2b+3c}+\frac{2c+3a}{b+2c+3a}+\frac{2a+3b}{c+2a+3b}\ge\frac{5}{2}\)
Chứng minh rằng với mọi a,b,c>0 ta có:
\(\frac{ab}{a+3b+2c}+\frac{bc}{b+3c+2a}+\frac{ca}{c+3a+2b}\le\frac{a+b+c}{6}\)
cho a,b,c>0
cmr \(\frac{5a^3-b^3}{ab+3b^2}+\frac{5b^3-c^3}{cb+3c^2}+\frac{5c^3-a^3}{ac+3a^2}\le a+b+c\)
Cmr:
\(\forall a,b,c\ge0\)
\(\frac{a^3b}{c}+\frac{a^3c}{b}+\frac{b^3c}{a}+\frac{b^3a}{c}+\frac{c^3a}{b}+\frac{c^3b}{a}\ge6abc\)
Ai nhanh mình k cho nhé!
Cho a,b,c lớn hơn 0
CMR : \(\frac{ab}{a+3b+2c}+\frac{bc}{b+3c+2a}+\frac{ac}{c+3a+2b}\le\frac{a+b+c}{6}\)