Theo BĐT C-S:
\(S^2=\left(\sqrt{a}+\sqrt{b}+\sqrt{c}+\sqrt{d}\right)^2\)
\(\le\left(1+1+1+1\right)\left(a+b+c+d\right)\)
\(=4\cdot\left(a+b+c+d\right)=4\left(a+b+c+d=1\right)\)
\(\Rightarrow S^2\le4\Rightarrow S\le2\)
Đẳng thức xảy ra khi a=b=c=d=1/4