a, (x3.x2.x).(1/8-3/2+3/2-1) b, (x3.x2y.xy2.y3).(1/8-1/4+1/12-1/27)
=x6.(-7/8) = x6.y6.9.(-17/216)
a, (x3.x2.x).(1/8-3/2+3/2-1) b, (x3.x2y.xy2.y3).(1/8-1/4+1/12-1/27)
=x6.(-7/8) = x6.y6.9.(-17/216)
8,Thực hiện phép tính
a,\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
b,\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
c,\(\frac{2x}{x^2+2xy}+\frac{y}{xy-2y^2}+\frac{4}{x^2-4y^2}\)
d,\(\frac{1}{x-y}+\frac{3xy}{y^3-x^3}+\frac{x-y}{x^2+xy+y^2}\)
e,\(\frac{2x+y}{2x^2-xy}+\frac{16x}{y^2-4x^2}+\frac{2x-y}{2x^2+xy}\)
f,\(\frac{1}{1-x}+\frac{1}{1+x}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}\)
Biến đổi mỗi biểu thức sau thành phân thức
\(A=\frac{\frac{1}{x}-\frac{2}{y}}{\frac{4x^2-y^2}{x}}\)
\(B=\frac{\frac{xy-y^2}{1+xy}-xy}{\frac{x^2-xy}{1+xy}-x^2}\)
\(C=\frac{\frac{x^3-x}{x+1}+\frac{2x-2}{1+\frac{x}{2}}}{\frac{x^3-3x^2}{x-3}-\frac{2x^2+8}{x+2}}\)
1 cho a+b=1 tính giá trị của biểu thức
H=a3+b3+3ab(a2+b2)+6a2b2(a+b)
2 \(\frac{x^3}{8}+\frac{x^2y}{4}+\frac{xy^2}{6}+\frac{y^3}{27}\) với x=8,y= -6
2) Giải phương trình
a) \(\frac{x+1}{x-2}+\frac{x-1}{x+2}=\frac{2\left(x^2+2\right)}{x^2-4}\)
b) \(\left(2x+3\right).\left(\frac{3x+8}{2-7x}+1\right)=\left(x-5\right).\left(\frac{3x+8}{2-7x}+1\right)\)
3) Rút gọn
a) \(\frac{2x-1}{x^3+1}+\frac{2x}{x^2-x+1}+\frac{-x}{x+1}+2\)
b) \(\frac{x+1}{2x-2}+\frac{x^2+3}{2-2x^2}+\frac{1}{1-x}-1,5\)
c) \(\left(\frac{x^2}{x^3-4x}-\frac{6}{3x-6}+\frac{1}{x+2}\right).\frac{x+2}{6}\)
d) \(\left(\frac{x}{xy-y^2}+\frac{2x-y}{xy-x^2}\right):\frac{x^2-2xy+y^2}{x^2y-xy^2}\)
e) \([\frac{1}{\left(2x-y\right)^2}+\frac{2}{4x^2-y^2}-\frac{1}{\left(2x+y\right)^2}].\frac{x^2+4xy+y^2}{16x}\)
Mn giúp mik vs mik đang cần gấp
help me
1) \(\frac{3-7x}{1+x}=\frac{1}{2}\)
2)\(\frac{x+1}{x-2}=\frac{1}{x^2-4}\)
3) \(\frac{y-1}{y-2}-\frac{5}{y+2}=\frac{12}{y^2-4}+1\)
4) \(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{4}{x^2+1}\)
5) \(1+\frac{1}{x+2}=\frac{12}{8-x^3}\)
6) \(\frac{x}{x-1}-\frac{2x}{x^2-1}=0\)
7) \(\frac{2x}{x+2}-\frac{x}{x-2}=\frac{-4x}{x^2-4}\)
8) \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
9) \(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8+6x}{16x^2-1}\)
10) \(\frac{2x-3}{x+2}-\frac{x+2}{x-2}=\frac{2}{x^2-4}\)
11)\(\frac{x-1}{x+2}-\frac{x}{x-2}=\frac{5x-2}{4-x^2}\)
12)\(\frac{1}{x+1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)
Ai giúp vs !!!
\(a.\frac{3x-7}{5}=\frac{2x-1}{3}\\ b.\frac{4x-7}{12}-x=\frac{3x}{8}\\ c.\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\\ d.\frac{5x-8}{3}=\frac{1-3x}{2}\\ e.\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\\ f.\frac{x-1}{\frac{2}{5}}-3-\frac{3x-2}{\frac{5}{4}}-2=1\)
\(\frac{x}{3}=\frac{y}{4}và\frac{y}{6}=\frac{z}{5}va3x-2y+5z=86\)
\(\frac{x}{5}=\frac{y}{7};xy=140\)
\(\frac{x-1}{9}+\frac{x-2}{8}=\frac{x-3}{7}+\frac{x-4}{6}\)
\(\frac{31-2x}{x+23}=\frac{9}{4}\)
\(4x=5y;xy-80=0\)
\(\frac{x+3}{8}-\frac{2}{x-3}\)
\(\frac{x^2}{6}=\frac{14}{25}\)
\(A,\left(\frac{x+1}{x-1}-\frac{x-1}{x+1}\right):\left(\frac{1}{x+1}-\frac{x}{1-x}+\frac{2}{x^2-1}\right)=\frac{4x}{\left(x+1\right)^2}\)
\(B,\frac{2+x}{2-x}:\frac{4x^2}{4-4x+x^2}\cdot\left(\frac{2}{2-x}-\frac{4}{8+x^2}\cdot\frac{4-2x+x^2}{2-x}\right)=\frac{1}{2x}\)
\(C,\left[\left(\frac{3}{x-y}+\frac{3x}{x^2-y^2}\right):\frac{2x+y}{x^2+2xy+y^2}\right]\cdot\frac{x-y}{3}=xy\)
Chứng minh đẳng thức ( tìm x)
mọi người giải dùm mình cảm ơn
Bài 2: Rút gọn phân thức
\(A=\frac{10x^2-7+5x-2xy}{1-2x^2+x}\)
Bài 3: Chứng minh rằng
a) \(\frac{x^2y+2xy^2+y^3}{2x^2+xy-y^2}=\frac{xy+y^2}{2x-y}\)
b) \(\frac{x^2+3xy+2y^2}{x^3+2x^2y-xy^2-2y^3}=\frac{1}{x-y}\)
Bài 4: Quy đồng mẫu thức các phân thức sau
a) \(\frac{5x}{\left(x+3\right)^3}\&\frac{x-4}{3x\left(x+2\right)^2}\)
b) \(\frac{x+1}{x-x^2}\&\frac{x+2}{2x^2+2-4x}\)