Question

Viết CTHH thực hiện chuyển hóa sau:  

a) KMnO₄-(1)->O₂-(2)->H₂O-(3)->H₂-(4)->FeO-(5)->FeCl₂
b) P-(1)->P₂O₅-(2)->H₂PO₄
c) K-(1)->K₂O-(2)->KOH-(3)->KCl

 

 

Answer 1

\(a,\left(1\right)2KMnO_4\underrightarrow{t^o}K_2MnO_4+MnO_2+O_2\\ \left(2\right)O_2+2H_2\underrightarrow{t^o}2H_2O\\ \left(3\right)2Na+2H_2O\rightarrow2NaOH+H_2\\ \left(4\right)H_2+FeO\underrightarrow{t^o}Fe+H_2O\\ \left(5\right)Fe+2HCl\rightarrow FeCl_2\)

\(b,\left(1\right)4P+5O_2\underrightarrow{t^o}2P_2O_5\\ \left(2\right)P_2O_5+3H_2O\rightarrow2H_3PO_4\)

\(c,\left(1\right)4K+O_2\underrightarrow{t^o}2K_2O\\ \left(2\right)K_2O+H_2O\rightarrow2KOH\\ \left(3\right)KOH+HCl\rightarrow KCl+H_2O\)

Answer 2

a.\(2KMnO_4\rightarrow\left(t^o\right)K_2MnO_4+MnO_2+O_2\)

\(2H_2+O_2\rightarrow\left(t^o\right)2H_2O\)

\(2H_2O\rightarrow\left(đp\right)2H_2+O_2\)

\(FeO+H_2\rightarrow\left(t^o\right)Fe+H_2O\)

\(Fe+\dfrac{1}{2}O_2\rightarrow\left(t^o\right)FeO\)

\(FeO+2HCl\rightarrow FeCl_2+H_2O\)

b.\(4P+5O_2\rightarrow\left(t^o\right)2P_2O_5\)

\(P_2O_5+3H_2O\rightarrow2H_3PO_4\)

c.\(4K+O_2\rightarrow\left(t^o\right)2K_2O\)

\(K_2O+H_2O\rightarrow2KOH\)

\(6KOH+3Cl_2\rightarrow\left(t^o\right)5KCl+KClO_3+3H_2O\)

Answer 3

$a,\left(1\right)2KMn{}^{}{}^{}{}^{}Mn{}^{}+Mn{}^{}+{}^{}\left(2\right){}^{}+2{}^{}{}^{}2{}^{}O\left(3\right)2Na+2{}^{}O\to 2NaOH+{}^{}\left(4\right){}^{}+FeO{}^{}Fe+{}^{}O\left(5\right)Fe+2HCl\to FeC{}^{}$