\(a,1,\left(27\right)=1+\frac{27}{99}=1+\frac{3}{11}=\frac{14}{11}\)
\(0,\left(423\right)=\frac{423}{999}=\frac{47}{111}\)
\(2,\left(15\right)=2+\frac{15}{99}=2+\frac{5}{33}=\frac{71}{33}\)
\(b,3,04\left(31\right)=3+\frac{431-4}{9990}=3+\frac{427}{9990}=\frac{3397}{9990}\)
\(1,8\left(34\right)=1+\frac{834-8}{990}=1+\frac{413}{495}=\frac{908}{495}\)