a)\(\frac{13}{35}\)\(=\)\(\frac{1}{7}+\frac{1}{5}+\frac{1}{35}\)
b)\(\frac{17}{63}=\frac{1}{7}+\frac{1}{9}+\frac{1}{63}\)
k cho mình nha
13/35=1/5+1/7+1/35
17/63=1/7+1/9+1/63
a ) \(\frac{13}{35}\)=\(\frac{1}{35}\)+\(\frac{7}{35}\)+\(\frac{5}{35}\)=\(\frac{1}{35}\)+\(\frac{1}{5}\)+\(\frac{1}{7}\)
b ) \(\frac{17}{63}\)=\(\frac{1}{63}\)+\(\frac{9}{63}\)+\(\frac{7}{63}\)=\(\frac{1}{63}\)+\(\frac{1}{7}\)+\(\frac{1}{9}\)