\(2^5.8^4=2^5.\left(2^3\right)^4=2^5.2^{12}=2^{17}\)
\(25^6.125^3=\left(5^2\right)^6.\left(5^3\right)^3=5^{12}.5^9=5^{21}\)
1- 2x2x2x2x2
2-8x8x8x8
3- 25x25x25x25x25x25
4- 125x125x125
\(2^5.8^4\)
\(=2^5.\left(2^3\right)^4\)
\(=2^5.2^{12}=2^{17}\)
\(25^6.125^3\)
\(=\left(5^2\right)^6.\left(5^3\right)^3\)
\(=5^{12}.5^9=5^{21}\)
25 . 84 = 25 . (23)4 = 25 . 212 = 217
256 . 1253 = (52)6 . (53)3 = 512 . 59 = 521
\(2^5\times8^4=2^5\times2^{12}=2^{5+12}=2^{17}\)
\(25^6\times125^3=25^6\times5^9=5^{12}\times5^9=5^{12+9}=5^{21}\)
ta có 2^5 . 8^4=2^5 . (2^3)^4
=2^5.2^3.2^3.2^3.2^3=2^5.2^3.4
=2^5.2^12(vì 3.4=12)
=2^17
ta có 25^6. 125^3= (5^2)^6.(5^3)^3
= 5^2.5^2.5^2.5^2.5^2.5^2.5^3.5^3.5^3
= 5^2.6 .5^3.3=5^12(vì 2.6 =12 ko viết được).5^9 (vì 3.3=9 ko viết đc )
=5^21
25 . 84 = 25 . ( 23)4 = 25 . 212 = 217
256 . 1253 = (52)6 . (53)3 = 512 . 59 = 521
k cho mk nhé! Mặc dù mk là đến sau.