Giải: Ta có: \(\widehat{AOC}=\frac{1}{4}.\widehat{AOB}\)
=> \(\widehat{AOC}=\frac{1}{4}.160^0=40^0\)
Do OC nằm giữa OA và OB nên \(\widehat{AOC}+\widehat{COB}=\widehat{AOB}\)
=> \(\widehat{BOC}=\widehat{AOB}-\widehat{AOC}=160^0-40^0=120^0\)
Vậy ...
tren mat phang ve 3 tia Oa Ob Oc sao cho goc aOb ke voi goc aOc va goc aOb = 30 do , goc aOc = 90do tinh so do goc bOc
ve goc AOB =130 do va tia OC nam giua 2 tia OA va OB sao cho goc COA =1/4 goc AOC .Tinh so do goc AOC va goc COB
bai 1: tren mot nua mat phang bo chua tia Oa ve tia Ob sao cho goc AOB=35 do va tia Oc sao cho goc AOC= 70 do
a, tia Ob co phai la tia phan giac cua goc AOC khong? vi sao?
b, ve tia OB` la tia doi cua tia OB. tinh so do goc ke bu voi goc AOB
Cho hai goc aOb va aOc ke nhau, goc aOb = 60, aOc= 60
a)Tinh goc bOc b) Cho Ob la tia doi cua Oe. Tính so do cua eOb. c)Ke ten cac goc nhon, goc tu, goc bet va cac goc ke bu co trong hinh ve
Cho hai goc ke nhau AOC va BOC. Goi OM, ON theo thu tu la tia phan giac cua cac goc AOC va BOC. Tinh goc MON theo goc AOB. Ap dung goc AOB = 120o
cho 2 goc ke bu AOB va AOC . Biet AOB = 124 . a)tinh so do goc AOB. b)tren cung 1 nua mat phang bo BC chua tia OA ve COD = 118. tia OD co la tia phan giac cua goc AOB khong ?vi sao?
cho 3 tia phan biet O,OB,OC sao cho goc AOB=goc BOC = goc AOC
a. cmr :trong 3 tia da cho khong co tia nao nam giua 2 tia con lai
b. tinh so do goc AOB = goc BOC =goc AOC
Câu hỏi: Cho tia AOB=144 do. Tia OC la tia phan giac cua goc do.ve cac tia ON va Om nam trong goc AOB sao cho goc Aom=bom=20 do a/ chung to oc la tia phan giac cua goc mon b/ve tia Ob' la tia doi cua tia BO.So sanh goc AOb;AOC;Boc
tren nua mat phang bo chua tia Oa ,ve hsi tia Ob va Oc sao cho goc aOb =150 do ,goc aOc =90 do .Om la tia pham giac cua goc aOc
On la tia phan giac cua goc bOc
a) chung to rang Oc nam giua Oa,Ob
b) tinh so do cac goc bOc=?,aOm=?,aOn=?,mOn=?
