\(32000\left(\dfrac{m}{h}\right)=51499,01\left(\dfrac{km}{h}\right);14\left(\dfrac{m}{s}\right)=50,4\left(\dfrac{km}{h}\right)\)
\(\Rightarrow38,5< 50,4< 51499,01\)
Vậy oto < tàu hỏa < xe máy
Chọn B
\(v_1=38,5\)km/h=10,7m/s
\(v_2=32000\)m/h=8,89m/s
\(v_3=14\)m/s
\(\Rightarrow v_2< v_1< v_3\)
Chọn D.