\(\dfrac{1}{2};\dfrac{2}{3};\dfrac{3}{4}=\dfrac{1}{2}=\dfrac{1\times6}{2\times6}=\dfrac{6}{12};\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12};\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\)
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