\(n_{tinhbột}=\dfrac{1,5\cdot1000\cdot80\%}{162n}=\dfrac{200}{27n}\left(mol\right)\)
\(\left(C_6H_{10}O_5\right)_n\rightarrow nC_6H_{12}O_6\rightarrow2nC_2H_5OH+2nCO_2\)
\(n_{C_2H_5OH}=2n_{tinhbột}=2n\cdot\dfrac{200}{27n}=\dfrac{400}{27}mol\)
Hiệu suất:
\(H=\dfrac{m_{thựctế}}{m_{líthuyết}}\cdot100\%\)
\(\Rightarrow m_{C_2H_5OH}=\dfrac{400}{27}\cdot46\cdot90\%=613,33kg\)