Question

Trung hòa 50 ml dd NaOH 2M cần V ml dd H2SO4 1M. Tính giá trị của V

Answer 1

\(n_{OH^-}=n_{NaOH}=0,05\cdot2=0,1mol\)

\(n_{H_2SO_4}=1\cdot\dfrac{V}{22,4}=\dfrac{V}{22,4}\)\(\Rightarrow n_{H^+}=\dfrac{5V}{56}\)

Để trung hòa\(\Rightarrow n_{OH^-}=n_{H^+}\)

\(\Rightarrow\dfrac{5V}{56}=0,1\Rightarrow V=1,12\left(l\right)\)

Answer 2

\(2NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O\)

\(n_{NaOH}= 0,05 . 2=0,1 mol\)

Theo PTHH:

\(n_{H_2SO_4}= \dfrac{1}{2}n_{NaOH}= 0,1 . \dfrac{1}{2}= 0,05 mol\)

\(V_{H_2SO_4}= \dfrac{0,05}{1}= 0,05 l \)