\(\frac{\sqrt{6}}{3+\sqrt{2}-\sqrt{3}}=\frac{\sqrt{6}\left(3+\sqrt{2}+\sqrt{3}\right)}{\left(3+\sqrt{2}-\sqrt{3}\right)\left(3+\sqrt{2}+\sqrt{3}\right)}=\frac{3\sqrt{6}+2\sqrt{3}+3\sqrt{2}}{\left(3+\sqrt{2}\right)^2-3}\)
Ban tiep tuc khu mau roi lai su dung truc can thuc 1 lan nua la se co ket qua