\(Tacó\) : \(A=8.c+7\)
\(B=8.d+1\)
\(\Leftrightarrow A+B=8c+7+8d+1=8.\left(c+d\right)+8\)
\(Vì\)\(8.\left(c+d\right)⋮8;8⋮8\)
\(\Leftrightarrow8.\left(c+d\right)+8⋮8\)
\(\Leftrightarrow\left(A+B\right)⋮8\)
Vậy có số dư là 0.
ban kia lam dung roi do
k tui nha
thanks