\(\left\{{}\begin{matrix}\overrightarrow{BA}=\left(3;-1\right)\\\overrightarrow{BC}=\left(-4;-2\right)\end{matrix}\right.\)
\(\Rightarrow cos\widehat{ABC}=cos\left(\overrightarrow{BA};\overrightarrow{BC}\right)=\dfrac{3.\left(-4\right)+1.2}{\sqrt{3^2+1^2}.\sqrt{\left(-4\right)^2+\left(-2\right)^2}}=-\dfrac{\sqrt{2}}{2}\)
\(\Rightarrow\widehat{ABC}=135^0\)