\(\dfrac{3}{2}-\dfrac{4}{5}=\dfrac{15}{10}-\dfrac{8}{10}=\dfrac{7}{10}\)
\(\dfrac{2}{3}+\dfrac{1}{2}=\dfrac{4}{6}+\dfrac{3}{6}=\dfrac{7}{6}\)
\(\dfrac{1}{2}\times\dfrac{3}{7}=\dfrac{1\times3}{2\times7}=\dfrac{3}{14}\)
\(\dfrac{2}{3}:\dfrac{3}{2}=\dfrac{2}{3}\times\dfrac{2}{3}=\dfrac{4}{9}\)