Question

Trình bày ra hộ mình

Answer 1

Lời giải:

$(-x^2)(2x^3+3x^2-2x+5)=-x^2.2x^3+(-x^2).3x^2-(-x^2).2x+5(-x^2)$

$=-2x^5-3x^4+2x^3-5x^2$

Đáp án A.

Answer 2

\(\left(-x^2\right).\left(2x^3+3x^2-2x+5\right)\)

\(=\left(-x^2.2x^3\right)+\left(-x^2.3x^2\right)+\left[-x^2.\left(-2x\right)\right]+\left(-x^2.5\right)\)

\(=-2x^5-3x^4+2x^3-5x^2\)

Chọn A

Answer 3

\(-x^2\left(2x^3+3x^2-2x+5\right)=-2x^5-3x^4+2x^3-5x^2\)