\(\left(x:\dfrac{2}{5}+\dfrac{1}{6}\right)\left(\dfrac{14}{15}+\dfrac{1}{5}x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x:\dfrac{2}{5}+\dfrac{1}{6}=0\\\dfrac{14}{15}+\dfrac{1}{5}x=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x:\dfrac{2}{5}=-\dfrac{1}{6}\\\dfrac{1}{5}x=-\dfrac{14}{15}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{15}\\x=-\dfrac{14}{3}\end{matrix}\right.\)
Tổng giá trị của `x` là
\(-\dfrac{1}{15}-\dfrac{14}{3}=-\dfrac{71}{15}\)
`(x:2/5+1/6).(14/15+1/5x )=0`
`@TH1:`
`x:2/5+1/6=0`
`x:2/5=0-1/6`
`x:2/5=-1/6`
`x=-1/6 xx 2/5`
`x=-1/15`
@TH2:`
`14/15+1/5x = 0`
`1/5x=0-14/15`
`1/5x = -14/15`
`x=-14/15 : 1/5`
`x=-14/15 xx 5`
`x=-14/3`
Vậy `x = {-1/15;-14/3}`
Tổng giá trị `x` thõa mãn là:
`-1/15+(-14/3)=-1/15-14/3 = -71/15`
Vậy..
