Gọi a là số bé, b là số lớn, ta có:
a + b = 102 ; a0 + b = a x 10 + b = 417.
=> 10a + b - (a + b) = 315
=> 10a + b - a - b = 315 => (10a - a) + (b - b) =315
=> 9a = 315 => a=35 => b= 102 - 35 = 67.
Vậy số lớn là 67.
TONG CUA 2 SO TU NHIEN LA 102.NEU THEM CHU SO 0 VAO BEN PHAI SO BE ROI CONG SO LON TA DUOC TONG MOI LA 417.VAY SO LON LA BAO NHIEU
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tong cua 2 so tu nhien la 102.neu them chu so 0 vao ben phai so be roi cong voi so lon ta duoc tong moi la 417
vay so lon la...........
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tong cua hai so tu nhien la 102..neu them chu so 0 vao ben phai so be roi cong so lon ta duoc 417.tim so lon
tong cua 2 so tu nhien la 102 . neu them so 0 vao ben phai so be roi cong so lon ta duoc 417 . tim so lon
tong hai stn la102neu them chu so 0 vao ben phai so be roi cong voi so lon ta duoc tong moi la 417.vay so lon la
