\(2+\dfrac{3}{4}=\dfrac{8}{4}+\dfrac{3}{4}=\dfrac{11}{4}\\ \dfrac{5}{7}:6=\dfrac{5}{7}\times\dfrac{1}{6}=\dfrac{5}{42}\\ 2-\dfrac{3}{5}=\dfrac{10}{5}-\dfrac{3}{5}=\dfrac{7}{5}\\ \dfrac{5}{9}\times\dfrac{2}{7}=\dfrac{10}{63}\)
a )\(\dfrac{11}{4}\) b)\(\dfrac{5}{42}\) c)\(\dfrac{7}{5}\) d) \(\dfrac{10}{63}\)