a) ( 3x-17) . 45= 46
( 3x -17) = 46: 45
( 3x-17) = 4
3x = 4+17
3x= 21
x= 21:3
x=7
Vậy....
b) 3 |x-5|-23=(-2)3
3 |x-5| -23 = -8
3 |x-5| = -8+23
3 |x-5| = 15
| x -5| = 15:3
|x-5| = 5
TH1: x- 5= 5
x= 5+5
x= 10
TH2: x -5 = -5
x= -5+5
x= 0
Vậy...
c) 96-3 (x+1)=42
3 ( x+1) = 96-42
3(x+1) = 54
x+1 = 54:3
x+1 = 18
x= 18-1
x= 17
Vậy...
\(a,\left(3x-17\right)\cdot4^5=4^6\)
\(\Rightarrow3x-17=4\)
\(\Rightarrow3x=21\)
\(\Rightarrow x=7\)
\(b,3\cdot\left|x-5\right|-23=\left(-2\right)^3\)
\(\Rightarrow3\cdot\left|x-5\right|-23=-8\)
\(\Rightarrow3\left|x-5\right|=15\)
\(\Rightarrow\left|x-5\right|=5\)
\(\Rightarrow x-5=\pm5\)
\(\Rightarrow\orbr{\begin{cases}x-5=5\\x-5=-5\end{cases}\Rightarrow\orbr{\begin{cases}x=10\\x=0\end{cases}}}\)
\(c,96-3\left(x+1\right)=42\)
\(\Rightarrow3\left(x+1\right)=54\)
\(\Rightarrow x+1=18\)
\(\Rightarrow x=17\)
\(d,48:\left(2x+1\right)-7=5\)
\(\Rightarrow48\left(2x+1\right)=12\)
\(\Rightarrow2x+1=4\)
\(\Rightarrow x=\frac{3}{2}\)
\(e,4\left(x+1\right)^3-5=3^3\)
\(\Rightarrow4\left(x+1\right)^3=32\)
\(\Rightarrow\left(x+1\right)^3=8\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)