`a)PTHH:`
`Zn + 2HCl -> ZnCl_2 + H_2`
`0,1` `0,2` `0,1` `(mol)`
`n_[Zn]=[6,5]/65=0,1(mol)`
`b)V_[H_2]=0,1.22,4=2,24(l)`
`c)V_[dd HCl]=[0,2]/2=0,1(l)`
\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\
pthh:Zn+2HCl\rightarrow ZnCl_2+H_2\)
0,1 0,2 0,1
\(V_{H_2}=0,1.22,4=2,24\left(l\right)\\
V_{HCl}=\dfrac{0,2}{2}=0,1\left(l\right)\)