\(\left(\sqrt{10}+1\right)\left(\sqrt{10}-1\right)=\left(\sqrt{10}\right)^2-1=10-1=9\)
Đúng cho mình nha
\(\sqrt{\sqrt{10}-1}.\sqrt{\sqrt{10}+1}=\sqrt{\left(\sqrt{10}-1\right)\left(\sqrt{10}+1\right)}=\sqrt{\left(\sqrt{10}\right)^2-1}=\sqrt{10-1}=\sqrt{9}=3\)
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