`@` `\text {Ans}`
`\downarrow`
`a)`
\(4\dfrac{2}{3}-2\dfrac{3}{4}\)
`=`\(\dfrac{3\times4+2}{3}-\dfrac{4\times2+3}{4}\)
`=`\(\dfrac{14}{3}-\dfrac{11}{4}=\dfrac{23}{12}\)
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\(4\dfrac{2}{3}=\dfrac{14}{3}\)
\(2\dfrac{3}{4}=\dfrac{11}{4}\)
=> \(\dfrac{14}{3}-\dfrac{11}{4}=\dfrac{56}{12}-\dfrac{33}{12}=\dfrac{23}{12}\)
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\(4\dfrac{2}{3}-2\dfrac{3}{4}\)
\(=\dfrac{14}{3}-\dfrac{11}{4}\)
\(=\dfrac{56}{12}-\dfrac{33}{12}\)
\(=\dfrac{23}{12}\)
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