F = \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}-\frac{3}{203}+\frac{3}{17}+\frac{3}{5}}=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{293}\right)}\)
F = \(\frac{2}{3}\)
\(F=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}-\frac{3}{293}+\frac{3}{17}+\frac{3}{5}}=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{293}\right)}{3\left(\frac{1}{7}-\frac{1}{293}+\frac{1}{17}+\frac{1}{5}\right)}=\frac{2}{3}\)