a) \(\frac{4^2.4^3}{2^{10}}\)\
\(=\frac{4^5}{\left(2^2\right)^{10}}=\frac{4^5}{4^{10}}=\frac{1}{4^5}\)
b) \(\frac{0,6^5}{0,2^6}=\frac{\left(0,2.3\right)^5}{0,2^6}=\frac{0,2^5.3^5}{0,2^6}=\frac{3^5}{0,2}=5.3^5\)
Tính \(A=\left(\frac{1}{4\cdot9}+\frac{1}{9\cdot14}+\frac{1}{14\cdot19}+...+\frac{1}{44\cdot49}\right)\cdot\frac{1-3-5-7-...-49}{89}\)
\(B=\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}-\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
\(\frac{1}{10\cdot9}-\frac{1}{9\cdot8}-\frac{1}{8\cdot7}-\frac{1}{7\cdot6}-\frac{1}{6\cdot5}-\frac{1}{5\cdot4}-\frac{1}{4\cdot3}-\frac{1}{3\cdot2}-\frac{1}{2\cdot1}\)
\(\frac{7}{3\cdot4}-\frac{9}{4\cdot5}+\frac{11}{5\cdot6}-\frac{13}{6\cdot7}+\frac{15}{7\cdot8}-\frac{17}{8\cdot9}+\frac{19}{9\cdot10}\)
Rút gọn
a) B=\(\frac{2^7\cdot9^3}{6^5\cdot8^2}\)
b) C = \(\frac{6^3+3\cdot6^2+3^3}{-13}\)
c) M = \(\frac{2:6^{18}-4^{10}\cdot98}{4^{10}\cdot3^{16}+6^{12}\cdot200}\)
Tính tổng:\(S=\frac{1}{1\cdot3}-\frac{1}{2\cdot4}+\frac{1}{3\cdot5}-\frac{1}{4\cdot6}+\frac{1}{5\cdot7}-\frac{1}{6\cdot8}+\frac{1}{7\cdot9}-\frac{1}{8\cdot10}\)
Tính hợp lý
a)\(\left(-\frac{1}{3}\right)^2\cdot\left(5\frac{1}{2}\right)^0+\left(-\frac{1}{3}\right)^5\cdot4\frac{1}{2}\)
b) \(\left(\frac{2^2\cdot2^3}{4^2\cdot16}\right)^{15};\left(\frac{2^6}{16^2}\right)^{10}\)
c)\(\frac{2^{15}\cdot9^4}{6^6\cdot8^3}\)
a)\(\left(-\frac{5}{2}\right)^2:\left(-15\right)-\left(-0,45+\frac{3}{4}\right)\cdot\left(-1\frac{5}{9}\right)\)
b)\(\left(\frac{-1}{3}\right)-\left(\frac{-3}{5}\right)^0+\left(1-\frac{1}{2}\right)^2:2\)
c)\(E=\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
d)\(\frac{5^4\cdot20^4}{25^5\cdot4^5}\)
Help me:
Tính:
( 2-1 + 3-1 ) : ( 2-1 - 3-1 ) + ( 2-1 : 20 ) :23
\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{^{8^4\cdot3^{12}-6^{11}}}\)
\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
a) \(\frac{0,8^5}{0,4^6}\) b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\) c)\(\frac{2^{15}\cdot9^4}{6^3\cdot8^3}\)
