Question

tính:

a,\(A=\left(\frac{1}{2}+1\right)\cdot\left(\frac{1}{3}+1\right)\cdot\left(\frac{1}{4}+1\right)\cdot...\cdot\left(\frac{1}{99}+1\right)\)

Answer 1

\(A=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot...\cdot\frac{100}{99}\)

\(A=\frac{3\cdot4\cdot5\cdot...\cdot100}{2\cdot3\cdot4\cdot...\cdot99}\)

\(A=\frac{100}{2}\)

\(A=50\)

Answer 2

A = 3/2 . 4/3 . 5/4 . ... . 100/99

A = (3.4.5....99  /  3.4.5...99) . 100/2

A = 50

Answer 3

\(A=\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right)...\left(\frac{1}{99}+1\right)\)

\(A=\left(\frac{3}{2}\right).\left(\frac{4}{3}\right)....\left(\frac{100}{99}\right)\)

\(A=\frac{3.4.5....100}{2.3.4....99}=\frac{100}{2}=50\)

Answer 4

A=\(\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right).\left(\frac{1}{4}+1\right)...\left(\frac{1}{99}+1\right)\)

A=\(\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}...\cdot\frac{100}{99}\)

A=\(\frac{3.4.5.....100}{2.3.4....99}\)

A=\(\frac{100}{2}=50\)