\(3^2\times\frac{1}{243}\times81^2\times\frac{1}{3^3}\)
Ta có :
\(=9\times\frac{1}{243}\times6561\times\frac{1}{27}\)
\(=\frac{1}{27}\times6561\times\frac{1}{27}\)
\(=243\times\frac{1}{27}\)
\(=9\)
ủng hộ mik nhé .
\(3^2.\frac{1}{243}.81^2.\frac{1}{3^3}\)
\(=3^2.\frac{1}{3^5}.\left(3^4\right)^2.\frac{1}{3^3}\)
\(=3^2.\frac{1}{3^5}.3^8.\frac{1}{3^3}\)
\(=3^2.3^8.\frac{1}{3^5}.\frac{1}{3^3}\)
\(=3^{10}.\frac{1}{3^8}\)
tíc mình nha