\(A=\left(1+100\right)\times100\div2=5050\)\(A=\left(1+100\right)\times100\div2=5050\)
\(B=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{9900}\)
\(\Rightarrow B=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(\Rightarrow B=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(\Rightarrow B=1-\frac{1}{100}=\frac{99}{100}\)
Vậy..................
A=1+2+3+4+...+99+100
Số số hạng:(100-1):1+1=100(số)
A=(100+1)x100:2=5050
Học tốt!