Question

Tính)

a) 5+3x5²/-8

b)10³+5x10²+5³/6³+3x6²+3³

 

 

Answer 1

\(b,\frac{10^3+5x10^2+5^3}{6^3+3x6^2+3^3}\)

\(=\frac{5\left(200+10^2+5^2\right)}{3\left(72+6^2+3^2\right)}\)

\(=\frac{5\left(200+100+25\right)}{3\left(72+36+9\right)}\)

\(=\frac{5.325}{3.117}\)

\(=\frac{125}{27}\)