Question

Tính:

A= ( 3.4.2^16)^2 / 11.2^13.4^11-16^9

Answer 1

\(\frac{1}{2}\)

tích nha nha nha nha

Làm ơn đi

Answer 2

bạn sai rồi

Oh

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)

\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{9.2}{9}=2\)

Answer 3

\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(A=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)

\(A=\frac{3^2.2^4.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(A=\frac{3^2.2^{36}}{11.2^{13}.2^{22}-2^{36}}\)

\(A=\frac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)

\(A=\frac{3^2.2^{36}}{\left(11-2\right).2^{35}}\)

\(A=\frac{3^2.2}{9}=\frac{18}{9}=2\)

Answer 4

1/393216 nha

Answer 5

2

 

Answer 6

2 ở đâu mà trừ v 11-2