b)
\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}\)
=\(\frac{1}{3}-\frac{1}{9}\)
=\(\frac{2}{9}\)
Ủng hộ mik nhá ^_^
a)
\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}.\)
=\(\frac{1}{2}-\frac{1}{5}\)
=\(\frac{3}{10}\)
b)
\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}\)
=\(\frac{1}{3}-\frac{1}{10}\)
=\(\frac{7}{30}\)
c)
\(\frac{3}{4}-\frac{1}{3}-\frac{1}{6}\)
=\(\frac{3}{4}-\left(\frac{1}{3}+\frac{1}{6}\right)\)
=\(\frac{3}{4}-\frac{1}{2}\)
=\(\frac{3}{4}-\frac{2}{4}=\frac{1}{4}\)
d)\(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{6}\)
= \(\frac{1}{6}+\frac{1}{4}-\frac{1}{6}\)
=\(\left(\frac{1}{6}-\frac{1}{6}\right)+\frac{1}{4}\)
=\(\frac{1}{4}\)
a, = 1/2-1/5
= 5/10-2/10=3/10
b, bn nhìn lại đề nhé
c,= 9/12-4/12-2/12
=1/4
d,=6/12-4/12+3/12-2/12
=1/4
bn nhìn đề câu b nha bn