Các câu hỏi tương tự
tính:A=1+3/2^3+4/2^4+5/2^5+...+100/2^100
tick cho ai lam nhanh
\(\dfrac{1+5+5^2+5^3+...+5^{100}}{1+4+4^2+4^3+...+4^{100}}\)
A=1+(3/2^3)+(4/2^4)+(5/2^5)+...+(100/2^100)
Tính A = 1 + 3/2^3 + 4/2^4 + 5/2^5 + ... + 100/2^100
Thu gọn tổng sau: F= 1+3/2^3+4/2^4+5/2^5+…+100/2^100
Chứng minh rằng:a. frac{1}{3^2}+frac{2}{3^3}+frac{3}{3^4}+frac{4}{3^5}+...+frac{99}{3^{100}}+frac{100}{3^{101}} frac{1}{4}b.frac{1}{2}-frac{1}{4}+frac{1}{8}-frac{1}{16}+frac{1}{32}-frac{1}{64} frac{1}{3}c.frac{1}{3}-frac{2}{3^2}+frac{3}{3^3}-frac{4}{3^4}+...+frac{99}{3^{99}}-frac{100}{3^{100}} frac{1}{16}d. frac{1}{5^2}-frac{2}{5^3}+frac{3}{5^4}-frac{4}{5^5}+...+frac{99}{5^{100}}-frac{100}{5^{101}} frac{1}{36}
Đọc tiếp
Chứng minh rằng:
a. \(\frac{1}{3^2}+\frac{2}{3^3}+\frac{3}{3^4}+\frac{4}{3^5}+...+\frac{99}{3^{100}}+\frac{100}{3^{101}}< \frac{1}{4}\)
b.\(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}< \frac{1}{3}\)
c.\(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...+\frac{99}{3^{99}}-\frac{100}{3^{100}}< \frac{1}{16}\)
d. \(\frac{1}{5^2}-\frac{2}{5^3}+\frac{3}{5^4}-\frac{4}{5^5}+...+\frac{99}{5^{100}}-\frac{100}{5^{101}}< \frac{1}{36}\)
C=1+3/2^3+4/2^4+5/2^5+....+100/2^100
B=\(\frac{1+5+5^2+5^3+...+5^{100}}{1+4+4^2+4^3+...+5^{100}}\)
Tính A= 1+(3/2^3)+(4/2^4)+(5/2^5)+........+(100/2^100)