Các câu hỏi tương tự
frac{1}{2}times10+9hept{begin{cases}?+5end{cases}}frac{1}{2}+frac{1}{2}+56+9+1hept{begin{cases}?+12end{cases}}frac{1}{2}+frac{1}{2}times3+9hept{begin{cases}?+6end{cases}}frac{1}{2}times6+67hept{begin{cases}?+13end{cases}}frac{1}{2}+frac{1}{2}times8+7hept{begin{cases}?+6end{cases}}5 BÀI TOÁN NHÉ!
Đọc tiếp
\(\frac{1}{2}\times10+9=\hept{\begin{cases}?\\+\\5\end{cases}}\)
\(\frac{1}{2}+\frac{1}{2}+56+9+1\hept{\begin{cases}?\\+\\12\end{cases}}\)
\(\frac{1}{2}+\frac{1}{2}\times3+9\hept{\begin{cases}?\\+\\6\end{cases}}\)
\(\frac{1}{2}\times6+67\hept{\begin{cases}?\\+\\13\end{cases}}\)
\(\frac{1}{2}+\frac{1}{2}\times8+7\hept{\begin{cases}?\\+\\6\end{cases}}\)
5 BÀI TOÁN NHÉ!
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abcdeg/123345\(\hept{\begin{cases}4256376387678\\687686687686856\\686786766666865\end{cases}}\hept{\begin{cases}a\\b\end{cases}}\)
\(2\times7+45=\hept{\begin{cases}?\\?\\?\end{cases}}\)
a.\(239\div67-6+-\frac{371}{78}+416\div9+3x+\left[45-89x+5y\right]\)
b. \(67+5x-\hept{\begin{cases}12\\78-9\\8-4x\end{cases}\div0}\)
làm 2 bài
Tính nhẩm
6 + 1 = ..... 6 + 6 = .....
6 + 0 = ..... 6 + 2 = .....
6 + 7 = ..... 7 + 6 = .....
6 + 3 = ..... 6 + 8 = .....
8 + 6 = ..... 6 + 4 = .....
6 + 9 = ..... 9 + 6 = .....
6 + 5 = ..... 6 + 10 = .....
10 + 6 = .....
program xoa_ky_tu;uses crt;var x,y:string; i,j,dem,max: integer; a:char;BEGINclrscr;write(nhap xau x : );readln(x);y:x; for i:1 to length(x) dobeginj:i+1;repeatif x[i]x[j] then delete(x,j,1)elsej:j+1;until (jlength(x));end;writeln(xau sau khi loai bo ki tu giong nhau la :,x); max:0;a: ;for i:1 to length(x) dobegindem:0;for j:1 to length(y) doif x[i]y[j] thendem:dem+1;if demmax thenbeginmax:dem;a:x[i];end;end;writeln(ki tu ,a, xuat hien ,max, lan);readln;end.
Đọc tiếp
program xoa_ky_tu;
uses crt;
var x,y:string;
i,j,dem,max: integer;
a:char;
BEGIN
clrscr;
write('nhap xau x : ');
readln(x);
y:=x;
for i:=1 to length(x) do
begin
j:=i+1;
repeat
if x[i]=x[j] then delete(x,j,1)
else
j:=j+1;
until (j>length(x));
end;
writeln('xau sau khi loai bo ki tu giong nhau la :',x);
max:=0;
a:=' ';
for i:=1 to length(x) do
begin
dem:=0;
for j:=1 to length(y) do
if x[i]=y[j] then
dem:=dem+1;
if dem>max then
begin
max:=dem;
a:=x[i];
end;
end;
writeln('ki tu ',a,' xuat hien ',max,' lan');
readln;
end.
Điền dấu > , < , =
8 + 5.....8 + 4
8 + 5.....8 + 6
18 + 10.....17 + 10
8 + 9.....9 + 8
18 + 9.....19 + 8
18 + 8.....19 + 9
\(6-3+9\times2\)
kb với mk nha nha
Viết số thích hợp vào chỗ chấm:
6 + 4…… + 4 106 + … 10
9 + 1…… + 1 109 + … 10
7 + 3 ……+ 3 10 7 +… 10
8 + 2 …… + 2 108 + … 10
Đọc tiếp
Viết số thích hợp vào chỗ chấm:
6 + 4=… … + 4 = 10 6 + … = 10 |
9 + 1=… … + 1 = 10 9 + … = 10 |
7 + 3 =… …+ 3 = 10 7 +… = 10 |
8 + 2 =… … + 2 = 10 8 + … =10 |