72003 chia het cho 72001
72002 chia het cho 72001
=> 72003 + 72002 chia het cho 7
=>
Ta có \(7^{2003}+7^{2002}\)
\(=7^{2001}.\left(7^2+7\right)\)
Ta thấy \(7^{2001}⋮7^{2001}\Rightarrow7^{2001}.\left(7^2+7\right)\)
Do đó \(7^{2003}+7^{2002}⋮7^{2001}\)
Vậy....
Tính :
7^2003 + 7^2002 chia hết cho 7^2001
7^2003 + 7^2002
= 7^2001 . 7^2 + 7^2001 . 7^1
= 7^2001 . 49 + 7^2001 . 7
= 7^2001 . ( 49 + 7 )
= 7^2001 . 56 chia hết cho 7^2001
Vậy 7^2003 + 7^2002 chia hết cho 7^2001 .