Question

Tính

Answer 1

\(\dfrac{6^2+2.6^2+2^3}{37}=\dfrac{6^2.1+2.6^2+2.2^2}{37}=\dfrac{2^2.3^2.1+2.2^2.3^2+2.2^2.1}{37}=\dfrac{2^2.\left(3^2.1+2.3^2+2\right)}{37}=\dfrac{2^2.\left[3^2.\left(1+2\right)+2\right]}{37}=\dfrac{2^2.\left(3^2.3+2\right)}{37}=\dfrac{2^2.\left(3^3+2\right)}{37}=\dfrac{2^2.29}{37}=\dfrac{116}{37}\)