\(a,A=\dfrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}=\dfrac{5.2^{2.15}.3^{2.9}-2^2.3^{20}.2^{3.9}}{5.2^{10}.2^{19}.3^{19}-7.2^{29}.3^{3.6}}\)
\(=\dfrac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{29}.3^{18}.\left(5.3-7\right)}=\dfrac{10-9}{15-7}=\dfrac{1}{8}\)
\(b,B=1+49.\dfrac{1}{49}.\left(2^6:2^5\right)=1+2=3\)
