Tìm x, y:
\(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
Tìm x;y biết rằng:
\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
Bài 2 Tìm x,y : \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
Tìm x,y biết
\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
I.tìm x và y biết rằng: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
(\(x-\left(\frac{31}{12}\right)^2=\left(\frac{49}{15}\right)^2-x=y^2\)
\(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\) tìm x,y
ai làm hộ mk với
bài 1 : tìm x: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
bài 2: tìm x : \(\left(8x-1\right)^{2n+1}=5^{2n+1}\)(n thuộc N)
tìm x ,y biết
\(x+\left(-\frac{3}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)