Question

tính và nêu cách tính giúp mình với ạ 

1/2004 +2 +1/2004 +3 +2/2004

Answer 1

2056/501

Answer 2

\(\frac{1}{2004}+2+\frac{1}{2004}+3+\frac{2}{2004}\)

\(=\frac{1}{2004}+\frac{2}{1}+\frac{1}{2004}+\frac{3}{1}+\frac{2}{2004}\)

\(=\frac{1}{2004}+\frac{4008}{2004}+\frac{1}{2004}+\frac{6012}{2004}+\frac{2}{2004}\)

\(=\frac{4009}{2004}+\frac{1}{2004}+\frac{6012}{2004}\)\(+\frac{2}{2004}\)

\(=\frac{4010}{2004}+\frac{6012}{2004}+\frac{2}{2004}\)

\(=\frac{10022}{2004}+\frac{2}{2004}\)

\(=\frac{10024}{2004}\)