\(n_{CO_2}=\dfrac{32,2}{44}\approx0,73\left(mol\right)\)
\(V_{CO_2}\approx0,73\cdot22,4=16,39\left(l\right)\)
n CO2=\(\dfrac{32,2}{44}=\dfrac{161}{220}\)=>V CO2=\(\dfrac{161}{220}.22,4=16,39l\)
Tính thể tích ở điều kiện nào em?
\(n_{co_2}=\dfrac{32,2}{44}\text{≈}0,7\left(mol\right)\)
\(=>V_{co_{2\left(ĐKT\right)}}\text{≈}0,7\cdot24\text{≈}17\left(l\right)\)
\(=>V_{CO_{2\left(Đktc\right)}}\text{≈}0,7\cdot22,4\text{≈}16\left(l\right)\)
