\(A=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^{100}}\)(1)
\(\Rightarrow3A=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{99}}\)(2)
Lấy (2) trừ đi (1) ta có :
\(2A=1-\frac{1}{3^{100}}\)
\(\Rightarrow A=\frac{\left(1-\frac{1}{3^{100}}\right)}{2}\)