Câu hỏi của Nguyễn Vân Ly

Question

tinh tong sau:A=22+24 +26+28+.......+22010

Minh Anh · Accepted Answer

$A=2^2+2^4+2^6+2^8+...+2^{2010}$$4A=2^4+2^6+2^8+2^{10}+...+2^{2012}$$4A-A=\left(2^4+2^6+2^8+2^{10}+...+2^{2012}\right)-\left(2^2+2^4+2^6+2^8+...+2^{2010}\right)$$3A=2^{2012}-2^2$$A=\frac{2^{2012}-2^2}{3}$Câu trả lời: $A=2^2+2^4+2^6+2^8+...+2^{2010}$$4A=2^4+2^6+2^8+2^{10}+...+2^{2012}$$4A-A=\left(2^4+2^6+2^8+2^{10}+...+2^{2012}\right)-\left(2^2+2^4+2^6+2^8+...+2^{2010}\right)$$3A=2^{2012}-2^2$$A=\frac{2^{2012}-2^2}{3}$

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