Question

tính tổng : \(\frac{3}{4}xyz^2+\frac{1}{2}xyz^2+\left(-\frac{1}{4}\right)xyz^2\)

Answer 1

\(=xyz^2\)

đúng không

Answer 2

\(\frac{3}{4}xyz^2+\frac{1}{2}xyz^2+\left(-\frac{1}{4}\right)xyz^2\)

=\(\left(\frac{3}{4}+\frac{1}{2}-\frac{1}{4}\right)xyz^2\)

=\(xyz^2\)

Answer 3

\(\frac{3}{4}xyz^2+\frac{1}{2}xyz^2+\left(-\frac{1}{4}\right)xyz^2\)

=\(xyz^2\left[\frac{3}{4}+\frac{1}{2}+\left(-\frac{1}{4}\right)\right]\)

=\(xyz^2.1\)

= \(xyz^2\)