\(\frac{1}{5.6}\)- \(\frac{1}{6.7}\)- \(\frac{1}{7.8}\) - ... - \(\frac{1}{2004.2005}\)
= \(\frac{1}{5}\)- \(\frac{1}{6}\)+ \(\frac{1}{6}\)- \(\frac{1}{7}\)+ \(\frac{1}{7}\)- \(\frac{1}{8}\)+ ... + \(\frac{1}{2004}\)- \(\frac{1}{2005}\)
=\(\frac{1}{5}\)- \(\frac{1}{2005}\)
= \(\frac{80}{401}\)