P = \(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{99}\right)\)
= \(\frac{1}{2}.\frac{2}{3}.....\frac{98}{99}\)
= \(\frac{1}{99}\)
P = 1 − 2 1 1 − 3 1 ... 1 − 99 1 = 2 1 . 3 2 ..... 99 98 = 99 1
P = 1 − 2 1 1 − 3 1 ... 1 − 99 1 = 2 1 . 3 2 ..... 99 98 = 99 1