Question

tính tích A=3/4x8/9x15/16x....x2499/2500 

Answer 1

TA CÓ ;

\(A=\frac{3}{4}.\frac{8}{9}...\frac{2499}{2500}\)

\(A=\frac{1.3}{2.2}.\frac{2.4}{3.3}...\frac{49.51}{50.50}\)

\(A=\frac{1.3.2.4...49.51}{2.2.3.3...50.50}\)

\(A=\frac{\left(1.2...49\right).\left(3.4...51\right)}{\left(2.3...50\right).\left(2.3...50\right)}\)

\(A=\frac{1.51}{50.2}=\frac{51}{100}\)

VẬY \(A=\frac{51}{100}\)