ối trời làm tắt không ổn
\(S^2=6-2\sqrt{3+2\sqrt{2}+1}=6-2\sqrt{\left(\sqrt{3}+1\right)^2}\)
\(S^2=6-2\left(\sqrt{3}+1\right)=6-2\sqrt{3}-2=4-2\sqrt{3}\)
\(S^2=\left(\sqrt{3}-1\right)^2\)
\(S=!\sqrt{3}-1!\)
\(S\le0\Rightarrow1-\sqrt{3}\)
Giao luu:
\(S^2=6-2.\sqrt{\left(3-\sqrt{5-2\sqrt{3}}\right)\left(3+\sqrt{5-2\sqrt{3}}\right)}\)
\(S^2=6-\sqrt{9-\left(5-2\sqrt{3}\right)}\)\(=6-\sqrt{4+2\sqrt{3}}=6-\left(2+\sqrt{3}\right)=4-\sqrt{3}\)
\(S=-\sqrt{4-\sqrt{3}}\)
Nhầm rồi
\(S^2=6-2\sqrt{4+2\sqrt{3}}=6-2\sqrt{\left(3+\sqrt{3}\right)^2}\\ \)
\(S^2=6-2\left(3+\sqrt{3}\right)=-2\sqrt{3}\) sao lại ra (-) nhỉ sai ở đâu vậy ta
