Question

Tính số mol:

1) 16 g C 

2) 26 g Zn 

3) 8 g NaOH 

4) 12,4 g P 

5) 31,5 g HNO₃ 

6)4,48 l khí N₂

7) 13,44 l khí Cl₂

8) 67200 ml khí CO₂

9) 35840 ml khí H₂

10) 20,16 l khí O₂

Answer 1

\(1.n_C=\dfrac{16}{12}=1,33\left(mol\right)\\ 2.n_{Zn}=\dfrac{26}{65}=0,4\left(mol\right)\\ 3.n_{NaOH}=\dfrac{8}{40}=0,2\left(mol\right)\\ 4.n_P=\dfrac{12,4}{31}=0,4\left(mol\right)\\ 5.n_{HNO_3}=\dfrac{31,5}{63}=0,5\left(mol\right)\\ 6.n_{N_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\\ 7.n_{Cl_2}=\dfrac{13,44}{22,4}=0,6\left(mol\right)\\ 8.n_{CO_2}=\dfrac{67,2}{22,4}=3\left(mol\right)\\ 9.n_{H_2}=\dfrac{35,84}{22,4}=1,6\left(mol\right)\\ 10.n_{O_2}=\dfrac{20,16}{22,4}=0,9\left(mol\right)\)

Answer 2

\(1,n_C=\dfrac{16}{12}\approx1,33(mol)\\ 2,n_{Zn}=\dfrac{26}{65}=0,4(mol)\\ 3,n_{NaOH}=\dfrac{8}{40}=0,2(mol)\\ 4,n_{P}=\dfrac{12,4}{31}=0,4(mol)\\ 5,n_{HNO_3}=\dfrac{31,5}{63}=0,5(mol)\\ 6,n_{N_2}=\dfrac{4,48}{22,4}=0,2(mol)\)