a) \(n_{Cu}=\dfrac{3,2}{64}=0,05\left(mol\right)\)
`=>` Số nguyên tử đồng: \(0,05.6.10^{23}=3.10^{22}\) (nguyên tử)
`=>` \(\left\{{}\begin{matrix}p=e=29.3.10^{22}=8,7.10^{23}\left(hạt\right)\\n=35.3.10^{22}=1,05.10^{24}\left(hạt\right)\end{matrix}\right.\)
b) \(n_{O_2}=\dfrac{16}{32}=0,5\left(mol\right)\Rightarrow n_O=2n_{O_2}=1\left(mol\right)\)
`=>` Số nguyên tử oxi: \(1.6.10^{23}=6.10^{23}\) (nguyên tử)
`=>` \(p=e=n=6.10^{23}.8=4,8.10^{24}\left(hạt\right)\)