Tính A = \(\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{3000}}{\frac{2999}{1}+\frac{2998}{2}+...+\frac{1}{2999}}\)(Trình bày rõ => tick )
Giúp mik vs Tính tổng sau: E=1-2+22-23+...+21000
Tính:1/2+1/3+...+1/3000 / 2999/1+2998/2+...+1/2999
1/2+1/3+1/4+...+1/300
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2999/1+2998/2+2997/3+...+1/2999
Cho N = 30 /1 + 30 / 2 + 30 / 3 +.....+ 30 / 3000 và M = 2999 / 1 + 2998 / 2 + 2997 / 3 + ...+ 1 / 2999
Tính N : M
Tính \(N=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{3000}}{\frac{2999}{1}+\frac{2998}{2}+\frac{2997}{3}+...+\frac{1}{2999}}\)
Bài 1 : Tính A = \(\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{3000}}{\frac{2999}{1}+\frac{2998}{2}+...+\frac{1}{2999}}\)(Giải rõ => tick )
A=
\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{3000}\)
\(\frac{2999}{1}+\frac{2998}{2}+\frac{2997}{3}+...+\frac{1}{2999}\)
4000:3000+4001:2999+4002:2998+...+6000:1000